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x/x^2-8=3
We move all terms to the left:
x/x^2-8-(3)=0
Domain of the equation: x^2!=0We add all the numbers together, and all the variables
x^2!=0/
x^2!=√0
x!=0
x∈R
x/x^2-11=0
We multiply all the terms by the denominator
x-11*x^2=0
We add all the numbers together, and all the variables
-11x^2+x=0
a = -11; b = 1; c = 0;
Δ = b2-4ac
Δ = 12-4·(-11)·0
Δ = 1
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1}=1$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-1}{2*-11}=\frac{-2}{-22} =1/11 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+1}{2*-11}=\frac{0}{-22} =0 $
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